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x^2-0.5x=0.5
We move all terms to the left:
x^2-0.5x-(0.5)=0
We add all the numbers together, and all the variables
x^2-0.5x-0.5=0
a = 1; b = -0.5; c = -0.5;
Δ = b2-4ac
Δ = -0.52-4·1·(-0.5)
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{2.25}}{2*1}=\frac{0.5-\sqrt{2.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{2.25}}{2*1}=\frac{0.5+\sqrt{2.25}}{2} $
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